PHP
·
发表于 5年以前
·
阅读量:8293
控制层
use frontend\models\StudUser;
use yii\data\Pagination;
use yii\db\Query;
/**
* 查询
*
*/
public function actionSearch()
{
//接值
$where=Yii::$app->request->get();
//实例化query
$query=new Query();
$query->from('stud_user');
//判断
if(isset($where['sex'])&&$where['sex']!=''){
//判断
if($where['sex']=='男'){
$query->andWhere(['stud_sex'=>0]);
}
if($where['sex']=='女'){
$query->andWhere(['stud_sex'=>1]);
}
}else{
$where['sex']='';
}
//年龄
if(isset($where['age'])&&$where['age']!=''){
$query->andWhere(['>','stud_age',$where['age']]);
}else{
$where['age']='';
}
//分页
$pagination = new Pagination(['totalCount' => $query->count()]);
//条数
$pagination->setPageSize('3');
//条件
$query->offset($pagination->offset)->limit($pagination->limit);
//执行
$userInfo=$query->all();
//print_r($userInfo);die;
return $this->render('search',['userInfo'=>$userInfo,'page'=>$pagination,'where'=>$where]);
}
模型层
<?php
namespace frontend\models;
use Yii;
use yii\db\ActiveRecord;
class StudUser extends ActiveRecord
{
/**
* 声明表名
*
*/
public static function tableName()
{
return '{{%stud_user}}';
}
/**
* 验证规则
*
*/
public function rules()
{
return [
['stud_age','integer'],
];
}
}
视图层
<?php
use yii\widgets\ActiveForm;
use yii\helpers\Url;
use yii\helpers\Html;
use yii\widgets\LinkPager;
?>
<?php
$form=ActiveForm::begin([
'action'=>Url::toRoute(['admin/search']),
'method'=>'get',
]);
echo '性别'," ",Html::input('text','sex',$where['sex']);
echo '年龄'," ",Html::input('text','age',$where['age']);
echo Html::submitButton('提交');
ActiveForm::end();
?>
<table class="table">
<tr>
<td>序号</td>
<td>姓名</td>
<td>年龄</td>
</tr>
<?php foreach($userInfo as $val):?>
<tr>
<td><?= $val['stud_id']?></td>
<td><?= $val['stud_name']?></td>
<td><?= $val['stud_age']?></td>
</tr>
<?php endforeach;?>
</table>
<?php
echo LinkPager::widget([
'pagination' => $page,
'nextPageLabel'=>'下一页'
]);?>
分页的样式在
LinkPager.php中
以上所述是小编给大家介绍的YII框架中搜索分页jQuery写法详解,希望对大家有所帮助,如果大家有任何疑问请给我留言,小编会及时回复大家的。在此也非常感谢大家对脚本之家网站的支持!