PHP
·
发表于 5年以前
·
阅读量:8308
本文实例讲述了CodeIgniter表单验证方法。分享给大家供大家参考,具体如下:
1.在D:\CodeIgniter\system\application\views目录下写一个视图文件myform.php
<html>
<head>
<title>My Form</title>
</head>
<body>
<?php echo $this->validation->error_string;?>
<?php echo form_open('form/index');?>
<h5>Username</h5>
<input type="text" name="username" value="" size="50" />
<h5>Password</h5>
<input type="text" name="password" value="" size="50" />
<h5>Password Confirm</h5>
<input type="text" name="passconf" value="" size="50" />
<h5>Email Address</h5>
<input type="text" name="email" value="" size="50" />
<div><input type="submit" value="Submit" /></div>
</form>
</body>
</html>
然后再写一个视图文件formsuccess.php
<html>
<head>
<title>My Form</title>
</head>
<body>
<h3>Your form was successfully submitted!</h3>
<p><?=anchor('form', 'Try it again!'); ?></p>
</body>
</html>
2.在D:\CodeIgniter\system\application\controllers目录下写一个控制器文件form.php
<?php
class Form extends Controller{
function index(){
$this->load->helper(array('form','url'));
$this->load->library('validation');
$rules['username'] = "required";
$rules['password'] = "required";
$rules['passconf'] = "required";
$rules['email'] = "required";
$this->validation->set_rules($rules);
// $this->validation->set_error_delimiters('<div class="error">','</div>');
$fields['username'] = 'Username';
$fields['password'] = 'Password';
$fields['passconf'] = 'Password Confirmation';
$fields['email'] = 'Email Address';
$this->validation->set_fields($fields);
if ($this->validation->run()==false) {
$this->load->view('MyView/myform');
}else {
$this->load->view('MyView/formsuccess.php');
}
}
}
?>
3.http://localhost:8888/index.php/form/index访问一下
Ok,结果都出来了
更多关于PHP相关内容感兴趣的读者可查看本站专题:《codeigniter入门教程》、《CI(CodeIgniter)框架进阶教程》、《php日期与时间用法总结》、《php面向对象程序设计入门教程》、《php字符串(string)用法总结》、《php+mysql数据库操作入门教程》及《php常见数据库操作技巧汇总》
希望本文所述对大家PHP程序设计有所帮助。